( bucko | 2021. 11. 19., p – 13:17 )

Teljes statisztika

awk -F\, \
'{
	for ( i= 1; i<=NF;i++)
		C[$i]++
}
END {
	for ( i= 1; i<=90;i++)
		print(i,C[i])
}'

A megoldás

awk -F\, \
'{
	for ( i= 1; i<=NF;i++)
		if ( $i <= 30 )
			C[$i]++
}
END {
	for ( i= 1; i<=30;i++)
		print(i, i in C ? C[i] : 0 )
}'